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      1 @node Iteration
      2 @subsection Iteration
      3 
      4 @c Since @deffn would put this whole complex form on one line in most
      5 @c output types, I've put the actual syntax after definition header.
      6 @c Maybe there's a better way?
      7 @deffn syntax do
      8 
      9 @format
     10 @code{(do ((}@svar{variable@sub{1}} @svar{init@sub{1}} @svar{step@sub{1}}@code{)}
     11      @dots{}@code{)}
     12     @code{(}@svar{test} @svar{expression} @dots{}@code{)}
     13   @svar{command} @dots{}@code{)}
     14 @end format
     15 
     16 Syntax: All of @svar{init}, @svar{step}, @svar{test}, and @svar{command} are expressions.
     17 
     18 Semantics:
     19 A @code{do} expression is an iteration construct.  It specifies a set of variables to
     20 be bound, how they are to be initialized at the start, and how they are
     21 to be updated on each iteration.  When a termination condition is met,
     22 the loop exits after evaluating the @svar{expression}s.
     23 
     24 A @code{do} expression is evaluated as follows:
     25 The @svar{init} expressions are evaluated (in some unspecified order),
     26 the @svar{variable}s are bound to fresh locations, the results of the
     27 @svar{init} expressions are stored in the bindings of the
     28 @svar{variable}s, and then the iteration phase begins.
     29 
     30 Each iteration begins by evaluating @svar{test}; if the result is
     31 false (@xref{Booleans}), then the @svar{command}
     32 expressions are evaluated in order for effect, the @svar{step}
     33 expressions are evaluated in some unspecified order, the
     34 @svar{variable}s are bound to fresh locations, the results of the
     35 @svar{step}s are stored in the bindings of the
     36 @svar{variable}s, and the next iteration begins.
     37 
     38 If @svar{test} evaluates to a true value, then the
     39 @svar{expression}s are evaluated from left to right and the values of
     40 the last @svar{expression} are returned.  If no @svar{expression}s
     41 are present, then the value of the @code{do} expression is unspecified.
     42 
     43 The region of the binding of a @svar{variable}
     44 consists of the entire @code{do} expression except for the @svar{init}s.
     45 It is an error for a @svar{variable} to appear more than once in the
     46 list of @code{do} variables.
     47 
     48 A @svar{step} can be omitted, in which case the effect is the
     49 same as if @code{(}@svar{variable} @svar{init} @svar{variable}@code{)} had
     50 been written instead of @code{(}@svar{variable} @svar{init}@code{)}.
     51 
     52 @lisp
     53 (do ((vec (make-vector 5))
     54      (i 0 (+ i 1)))
     55     ((= i 5) vec)
     56   (vector-set! vec i i)) @result{} #(0 1 2 3 4)
     57 
     58 (let ((x '(1 3 5 7 9)))
     59   (do ((x x (cdr x))
     60        (sum 0 (+ sum (car x))))
     61       ((null? x) sum))) @result{} 25
     62 @end lisp
     63 
     64 @end deffn
     65 
     66 @deffn syntax let @svar{variable} @svar{bindings} @svar{body}
     67 
     68 ``Named @code{let}'' is a variant on the syntax of @code{let} which provides
     69 a more general looping construct than @code{do} and can also be used to express
     70 recursion.
     71 It has the same syntax and semantics as ordinary @code{let}
     72 except that @svar{variable} is bound within @svar{body} to a procedure
     73 whose formal arguments are the bound variables and whose body is
     74 @svar{body}. Thus the execution of @svar{body} can be repeated by
     75 invoking the procedure named by @svar{variable}.
     76 
     77 @lisp
     78 (let loop ((numbers '(3 -2 1 6 -5))
     79            (nonneg '())
     80            (neg '()))
     81   (cond ((null? numbers) (list nonneg neg))
     82         ((>= (car numbers) 0)
     83          (loop (cdr numbers)
     84                (cons (car numbers) nonneg)
     85                neg))
     86         ((< (car numbers) 0)
     87          (loop (cdr numbers)
     88                nonneg
     89                (cons (car numbers) neg)))))
     90           @result{} ((6 1 3) (-5 -2))
     91 @end lisp
     92 
     93 @end deffn